Question

Dichromate ion is treated with base, the oxidation number of $Cr$ in the product formed is ____.

Answer 1

Answer: 6

$C{r}_2{O}_7^{2-}+O{H}^{-}⟶Cr{O}_4^{2-}$

Oxidation state of $Cr$ in $Cr{O}_4^{2-}$ is +6