Question

Determine the oxidation number of $Xe$ atom in $B{a}_{2}Xe{O}_6$

• A. $+8$
• B. $-8$
• C. $+5$
• D. $-7$

Answer 1

Answer: (A)

Let the oxidation number of $Xe$ be $‘a’$ , then
$2\times 2+a+6\times (-2)=0$
Hence, $a=+8$