Question

$\Delta G^{\circ }$ for the reaction, $C{u}^{2+}+Fe\to F{e}^{2+}+Cu$ is
(Given : $E_{C{u}^{2+}/Cu}^{\circ }=+0.34V$, $E_{F{e}^{2+}/Fe}^{\circ }=-0.44V$)

• A. $11.44kj$
• B. $180.8kj$
• C. $150.5kj$
• D. $28.5kj$

Answer 1

Answer: (C)

$E_{cell}^{\circ }=E_{C{u}^{2+}/Cu}^{\circ }-E_{F{e}^{2+}/Fe}^{\circ }$
$=0.34V-\left(-0.44\right)V=0.78V$
$\Delta G^{\circ }=-nF{E}_{cell}^{\circ }$
$=-2\times 96500\times 0.78$
$=150540J$ or $150.5kJ$