Question

Degree of dissociation of $0.1NC{H}_{3}COOH$ is $(K_{\text{acid}}=1\times 10^{-5})$

• A. $10^{-5}$
• B. $10^{-4}$
• C. $10^{-3}$
• D. $10^{-2}$

Answer 1

Answer: (D)

For a weak acid, degree of dissociation,
$\alpha =\sqrt{\frac{K_a}{C}}$
$=\sqrt{\frac{1\times 10^{-5}}{10^{-1}}}$
$=10^{-2}$