Define relations R1 and R2 on set A=[2,3,5,7,10] as x R1 y if x(y-1) and x R2 y if x+y=10, then the relation R given by R =R1 ∩ R2 is

Question

Define relations R1 and R2 on set A=[2,3,5,7,10] as x R1 y if x(y-1) and x R2 y if x+y=10, then the relation R given by R =R1 ∩ R2 is (A)   (B) (3,7)  (C)  (3,7),(5,5)  (D) None of these

Tardigrade Admin · Accepted Answer

A= 2,3,5,7,10 R1= (x, y): x /(y-1) ; R1 ⊆ A × A and R2= (x, y): x+y=10 ; R2 ⊆ A × A ⇒ R1= (2,3),(2,5),(2,7),(3,7),(3,10) and R2= (3,7),(5,5),(7,3) ⇒ R=R1 ∩ R2= (3,7)

Q. Define relations $R_{1}$ and $R_{2}$ on set $A = [2, 3, 5, 7, 10]$ as $x R_{1} y$ if $x (y - 1)$ and $x R_{2} y$ if $x + y = 10$ , then the relation $R$ given by $R$ $= R_{1} \cap R_{2}$ is

${}$

$(3, 7)}$

${(3, 7), (5, 5)}$

None of these

Q. Define relations R1​ and R2​ on set A=[2,3,5,7,10] as xR1​y if x(y−1) and xR2​y if x+y=10, then the relation R given by R =R1​∩R2​ is

{}

(3,7)}

{(3,7),(5,5)}

None of these

A={2,3,5,7,10} R1​={(x,y):x/(y−1)}; R1​⊆A×A and R2​={(x,y):x+y=10}; R2​⊆A×A ⇒R1​={(2,3),(2,5),(2,7),(3,7),(3,10)} and R2​={(3,7),(5,5),(7,3)} ⇒R=R1​∩R2​={(3,7)}

Q. Define relations $R_{1}$ and $R_{2}$ on set $A = [2, 3, 5, 7, 10]$ as $x R_{1} y$ if $x (y - 1)$ and $x R_{2} y$ if $x + y = 10$ , then the relation $R$ given by $R$ $= R_{1} \cap R_{2}$ is

${}$

$(3, 7)}$

${(3, 7), (5, 5)}$