De-Broglie wavelength of an electron accelerated by a voltage of 50 textV is close to (|e| = 1.6 × (10)- 19 C , me = 9.1 × (10)- 31 k g , h = 6.6 × (10)- 34 J s)

Question

De-Broglie wavelength of an electron accelerated by a voltage of 50 textV is close to (|e| = 1.6 × (10)- 19 C , me = 9.1 × (10)- 31 k g , h = 6.6 × (10)- 34 J s) (A) 0.5 textÅ (B) 1.2 textÅ (C) 1.7 textÅ (D) 2.4 textÅ

Tardigrade Admin · Accepted Answer

De-Broglie wavelength λ in given by λ =(h/m v)=(h/√2 m e V) and for electron λ =(12.27 overset° A/√V) =(12.27 overset° A/√50) =1.7 overset° A

Q. De-Broglie wavelength of an electron accelerated by a voltage of $50 V$ is close to $(∣ e ∣ = 1.6 \times (10)^{- 19} C, m_{e} = 9.1 \times (10)^{- 31} k g, h = 6.6 \times (10)^{- 34} J s)$

$0.5 Å$

$1.2 Å$

$1.7 Å$

$2.4 Å$

De-Broglie wavelength $λ$ in given by
$λ = \frac{h}{m v} = \frac{h}{2 m e V}$
and for electron $λ = \frac{12.27 A ^{\circ}}{V}$
$= \frac{12.27 A ^{\circ}}{50}$
$= 1.7$ $A^{\circ}$

Q. De-Broglie wavelength of an electron accelerated by a voltage of 50V is close to (∣e∣=1.6×(10)−19C,me​=9.1×(10)−31kg,h=6.6×(10)−34Js)

0.5Å

1.2Å

1.7Å

2.4Å