Question

$\frac{d}{dx}\left(\frac{\tan x+\sec x-1}{\tan x-\sec x+1}\right)$ is equal to:

• A. $\sec x(\tan x-\sec x)$
• B. $\sec x(\sec x-\tan x)$
• C. $\sec x(\sec x+\tan x)$
• D. none

Answer 1

Answer: (C)

Answer is $\sec x(\sec x+\tan x)$