CuS is dissolved in dil. HNO3. Balanced equation with correct products is

Question

CuS is dissolved in dil. HNO3. Balanced equation with correct products is (A) CuS + 2H+ + 3NO-3 → Cu(NO3)2 + H2S + H2O + NO2 (B) 3CuS + 8H++ 8NO-3 → 3Cu(NO3) 2 + 3S + 4H2O + 2NO (C) CuS + 4NO-3 → Cu(NO3)2 + H2S + H2O (D) None of the above in correct

Tardigrade Admin · Accepted Answer

CuS (black ppt.) on boiling with HNO3 results in the formation of colloidal S and blue coloured solution of Cu(NO3)2.

Q. CuS is dissolved in dil. $H N O_{3}$ . Balanced equation with correct products is

$C u S + 2 H^{+} + 3 N O_{3}^{-} \to C u (N O_{3})_{2} + H_{2} S + H_{2} O + N O_{2}$

$3 C u S + 8 H^{+} + 8 N O_{3}^{-} \to 3 C u (N O_{3})_{2} + 3 S + 4 H_{2} O + 2 NO$

$C u S + 4 N O_{3}^{-} \to C u (N O_{3})_{2} + H_{2} S + H_{2} O$

None of the above in correct

CuS (black ppt.) on boiling with $H N O_{3}$ results in the formation of colloidal S and blue coloured solution of $C u (N O_{3})_{2}$ .

Q. CuS is dissolved in dil. HNO3​. Balanced equation with correct products is

CuS+2H++3NO3−​→Cu(NO3​)2​+H2​S+H2​O+NO2​

3CuS+8H++8NO3−​→3Cu(NO3​)2​+3S+4H2​O+2NO

CuS+4NO3−​→Cu(NO3​)2​+H2​S+H2​O