Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
CrO5 has two (.-O-O.) bonds. Oxidation state of Cr in CrO5 is:
Q.
C
r
O
5
has two
(
−
O
−
O
)
bonds. Oxidation state of
C
r
in
C
r
O
5
is:
67
167
NTA Abhyas
NTA Abhyas 2020
Report Error
A
+
5
B
+
3
C
+
6
D
−
10
Solution:
C
r
O
5
has 2 peroxy linkage.