Correct set of four quantum numbers for valence electron of rubidium (Z = 37) is

Question

Correct set of four quantum numbers for valence electron of rubidium (Z = 37) is (A) 5, 0, 0, +(1/2)  (B) 5,1, 0, +(1/2)  (C) 5, 1, 1, +(1/2)  (D) 6, 0, 0, +(1/2)

Tardigrade Admin · Accepted Answer

Electronic configuration of Rb (Z=37) is 1 s2, 2 s2, 2 p6, 3 s2, 3 p6, 3 d10, 4 s2, 4 p6, 5 s1 So, for the valence shell electron (5 s1) n=5, l=0, m=0, s=+(1/2)

Q. Correct set of four quantum numbers for valence electron of rubidium ( $Z = 37$ ) is

5, 0, 0, $+ \frac{1}{2}$

5,1, 0, $+ \frac{1}{2}$

5, 1, 1, $+ \frac{1}{2}$

6, 0, 0, $+ \frac{1}{2}$

Electronic configuration of $R b (Z = 37)$ is
$1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{2}, 4 p^{6}, 5 s^{1}$
So, for the valence shell electron $(5 s^{1})$
$n = 5, l = 0, m = 0, s = + \frac{1}{2}$

Q. Correct set of four quantum numbers for valence electron of rubidium (Z=37) is

5, 0, 0, +21​

5,1, 0, +21​

5, 1, 1, +21​

6, 0, 0, +21​