Consider the reaction, 2N2O5 → 4NO2 + O2 In the reaction NO2 is being formed at the rate of 0.0125 mol L-1 s-1. What is the rate of reaction at this time?

Question

Consider the reaction, 2N2O5 → 4NO2 + O2 In the reaction NO2 is being formed at the rate of 0.0125 mol L-1 s-1. What is the rate of reaction at this time? (A) 0.0018 mol L-1 s-1 (B) 0.0031 mol L-1 s-1 (C) 0.0041 mol L-1 s-1 (D) 0.050 mol L-1 s-1

Tardigrade Admin · Accepted Answer

Rate =(1/4) (d[NO2]/dt) =(1/4)×0.0125 =0.0031 mol L-1s-1

Q. Consider the reaction, $2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$ In the reaction $N O_{2}$ is being formed at the rate of $0.0125 m o l L^{- 1} s^{- 1}$ . What is the rate of reaction at this time?

$0.0018 m o l L^{- 1} s^{- 1}$

$0.0031 m o l L^{- 1} s^{- 1}$

$0.0041 m o l L^{- 1} s^{- 1}$

$0.050 m o l L^{- 1} s^{- 1}$

Rate $= \frac{1}{4} \frac{d [ N O _{2} ]}{d t}$
$= \frac{1}{4} \times 0.0125$
$= 0.0031 m o l L^{- 1} s^{- 1}$

Q. Consider the reaction, 2N2​O5​→4NO2​+O2​ In the reaction NO2​ is being formed at the rate of 0.0125molL−1s−1. What is the rate of reaction at this time?

0.0018molL−1s−1

0.0031molL−1s−1

0.0041molL−1s−1

0.050molL−1s−1