As, m(12H)=2.014082u
and m(23He)=3.016029
and m(01n)=1.008665 Δm= mass defect =2m(12H)−m3(23He)−m(01n) =2×2.014082−3.016029−1.008665 ⇒Q-value =Energy liberated in reaction =[ mass ( reactants )−mass( products )]×931.5 =Δm×931.5MeV=3.232MeV
As Q-value is positive, so no threshold energy is required.