Consider the Linear Programming Problem Maximum Z = 4x + y Subject to x + y le 50 x + y ge 100 x,y ge 0 The maximum value of Z is

Question

Consider the Linear Programming Problem Maximum Z = 4x + y Subject to x + y le 50 x + y ge 100 x,y ge 0 The maximum value of Z is (A) 0 (B) 50 (C) 100 (D) does not exist

Tardigrade Admin · Accepted Answer

Given, Z=4 x+y <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/bfbca6994a7e22234a0221ada90d00b6-.png" /> and x+y ≤ 50, x+y ≥ 100 x, y ≥ 0 Hence, it is clear from the graph that it is not bounded, region. so maximum value cannot be determined.

Q. Consider the Linear Programming Problem Maximum
$Z = 4 x + y$
Subject to $x + y \leq 50$
$x + y \geq 100$
$x, y \geq 0$
The maximum value of $Z$ is

0

50

100

does not exist

Given, $Z = 4 x + y$

and $x + y \leq 50, x + y \geq 100$
$x, y \geq 0$
Hence, it is clear from the graph that it is not bounded, region. so maximum value cannot be determined.

Q. Consider the Linear Programming Problem Maximum Z=4x+y Subject to x+y≤50 x+y≥100 x,y≥0 The maximum value of Z is

0

50

100

does not exist

Given, Z=4x+y and x+y≤50,x+y≥100 x,y≥0 Hence, it is clear from the graph that it is not bounded, region. so maximum value cannot be determined.

Q. Consider the Linear Programming Problem Maximum
$Z = 4 x + y$
Subject to $x + y \leq 50$
$x + y \geq 100$
$x, y \geq 0$
The maximum value of $Z$ is

Given, $Z = 4 x + y$

and $x + y \leq 50, x + y \geq 100$
$x, y \geq 0$
Hence, it is clear from the graph that it is not bounded, region. so maximum value cannot be determined.