Consider the given case Magnetic field of 1 T is applied to this arrangement. If connecting wires and rod have negligible resistance. Then, the current through 5 Ω resistor is ldots ldots mA. .

Question

Consider the given case <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-m1wkml6jknx0humy.jpg" /> Magnetic field of 1 T is applied to this arrangement. If connecting wires and rod have negligible resistance. Then, the current through 5 Ω resistor is ldots ldots mA. . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

The formula for motional emf is ϵ =Blv Therefore, the current in the resistor i=(B l v/R)=(1 × 0 . 1 × 2/5)=40 mA

Q. Consider the given case

Magnetic field of $1 T$ is applied to this arrangement. If connecting wires and rod have negligible resistance. Then, the current through $5 Ω$ resistor is $\dots\dots m A .$ .

The formula for motional emf is $ϵ = Bl v$
Therefore, the current in the resistor $i = \frac{Bl v}{R} = \frac{1 \times 0.1 \times 2}{5} = 40 m A$

Q. Consider the given case Magnetic field of 1T is applied to this arrangement. If connecting wires and rod have negligible resistance. Then, the current through 5Ω resistor is ……mA. .

The formula for motional emf is ϵ=Blv Therefore, the current in the resistor i=RBlv​=51×0.1×2​=40mA

Q. Consider the given case

Magnetic field of $1 T$ is applied to this arrangement. If connecting wires and rod have negligible resistance. Then, the current through $5 Ω$ resistor is $\dots\dots m A .$ .

The formula for motional emf is $ϵ = Bl v$
Therefore, the current in the resistor $i = \frac{Bl v}{R} = \frac{1 \times 0.1 \times 2}{5} = 40 m A$