Consider the following reactions: NaCl + K 2 Cr 2 O 7+ underset( text conc.) H 2 SO 4 arrow A + side products A + NaOH arrow B + Side products B + underset text (dilute)H 2 SO 4+ H 2 O 2 arrow C Side products The sum of the total number of atoms in one molecule each of A and B and C is

Question

Consider the following reactions: NaCl + K 2 Cr 2 O 7+ underset( text conc.) H 2 SO 4 arrow A + side products A + NaOH arrow B + Side products B + underset text (dilute)H 2 SO 4+ H 2 O 2 arrow C Side products The sum of the total number of atoms in one molecule each of A and B and C is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

NaCl+K2(Cr)2O7+H2(SO)4 arrow underset(A )(CrO)2(Cl)2+ Side product underset(A )(CrO)2(Cl)2+NaOH arrow underset( B )(Na)2 (CrO)4 + Side product underset(B )(Na)2 (CrO)4 + H2 (SO)4+H2O2 arrow underset(C )(CrO)5+ Side product

Q. Consider the following reactions:
$N a Cl + K_{2} C r 2 O_{7} + (conc.) H_{2} S O_{4} \to A +$ side products
$A + N a O H \to B +$ Side products
$B + (dilute) H_{2} S O_{4} + H_{2} O_{2} \to C$ Side products
The sum of the total number of atoms in one molecule each of $A$ and $B$ and $C$ is

$N a Cl + K_{2} (C r)_{2} O_{7} + H_{2} (SO)_{4} \to (A) (C r O)_{2} (Cl)_{2} +$ Side product
$(A) (C r O)_{2} (Cl)_{2} + N a O H \to (B) (N a)_{2} (C r O)_{4} +$ Side product
$(B) (N a)_{2} (C r O)_{4} + H_{2} (SO)_{4} + H_{2} O_{2} \to (C) (C r O)_{5} +$ Side product

Q. Consider the following reactions: NaCl+K2​Cr2O7​+( conc.) H2​SO4​​→A+ side products A+NaOH→B+ Side products B+ (dilute)H2​SO4​​+H2​O2​→C Side products The sum of the total number of atoms in one molecule each of A and B and C is

NaCl+K2​(Cr)2​O7​+H2​(SO)4​→(A)(CrO)2​​(Cl)2​+ Side product (A)(CrO)2​​(Cl)2​+NaOH→(B)(Na)2​(CrO)4​+​ Side product (B)(Na)2​(CrO)4​+H2​(SO)4​​+H2​O2​→(C)(CrO)5​​+ Side product

Q. Consider the following reactions:
$N a Cl + K_{2} C r 2 O_{7} + (conc.) H_{2} S O_{4} \to A +$ side products
$A + N a O H \to B +$ Side products
$B + (dilute) H_{2} S O_{4} + H_{2} O_{2} \to C$ Side products
The sum of the total number of atoms in one molecule each of $A$ and $B$ and $C$ is

$N a Cl + K_{2} (C r)_{2} O_{7} + H_{2} (SO)_{4} \to (A) (C r O)_{2} (Cl)_{2} +$ Side product
$(A) (C r O)_{2} (Cl)_{2} + N a O H \to (B) (N a)_{2} (C r O)_{4} +$ Side product
$(B) (N a)_{2} (C r O)_{4} + H_{2} (SO)_{4} + H_{2} O_{2} \to (C) (C r O)_{5} +$ Side product