Question

Consider the following reactions:
$A\to P1;B\to P2;C\to P3;D\to P4$
The order of the above reactions are $a,b,c,$ and $d$, respectively. The following graph is obtained when log [rate] vs. $\log [$ conc $]$ are plotted:

Among the following , the correct sequence for the order of the reactions is:

• A. a > b > c > d
• B. c > a > b > d
• C. d > b > a > c
• D. d > a > b > c

Answer 1

Answer: (C)

Rate law $R=K$ [conc.] ${}^n[n\to$ order $]$

$\log ($ Rate $)=\log K+n\log [$ conc.$]$

For log(rate) $v/s$ log [conc.] graph

[Slope $=n]$

As slope increases order (n) increases

$\therefore$ Order $d>b>a>C$