Question

Consider the following reaction

$C{H}_{3}Br+Mg\stackrel{ether}{\to }A\stackrel{HCHO}{\to }B\stackrel{HOH}{\to }C.$ Compound $C$ is

• A. Acetic acid
• B. Acetaldehyde
• C. Ethyl alcohol
• D. Formic acid

Answer 1

Answer: (C)

${\text{CH}}_{\text{3}}\text{Br}\text{+}\text{Mg}{\to }_{\text{Δ}}^{\text{Ether}}{\text{CH}}_{\text{3}}\text{MgBr}{\to }_{\text{2)}{\text{H}}^{\text{+}}{\text{/H}}_{\text{2}}\text{O}}^{\text{1)}\text{HCHO}}{\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}\text{OH}$