Consider the following gaseous equilibria with equilibrium constants K1 and K2 respectively SO2(g)+(1/2)O2(g)SO3(g) 2SO3(g)2SO2(g)+O2(g) The equilibrium constants are related as

Question

Consider the following gaseous equilibria with equilibrium constants K1 and K2 respectively SO2(g)+(1/2)O2(g)SO3(g) 2SO3(g)2SO2(g)+O2(g) The equilibrium constants are related as (A)  K12=(1/K2)  (B)  2K1=K22  (C)  K2=(2/K12)  (D)  K22=(1/K1)

Tardigrade Admin · Accepted Answer

For the reaction, SO2(g)+(1/2)O2(g)SO3(g) Equilibrium constant, K1=([SO3]/[SO2][O2]1/2) ?.(i) For the reaction, 2SO3(g)2SO2(g)+O2(g) Equilibrium constant, K2=([SO2]2[O2]/[SO3]2) .....(ii) On squaring both sides in Eq. (i), we get K12=([SO3]2/[SO2]2[O2]) ??(iii) Eqs. (ii) × Eq. (iii), we get K12× K2=1 or K2=(1/K12) or K12=(1/K2)

Q. Consider the following gaseous equilibria with equilibrium constants $K_{1}$ and $K_{2}$ respectively $S O_{2} (g) + \frac{1}{2} O_{2} (g) S O_{3} (g)$ $2 S O_{3} (g) 2 S O_{2} (g) + O_{2} (g)$ The equilibrium constants are related as

$K_{1}^{2} = \frac{1}{K _{2}}$

$2 K_{1} = K_{2}^{2}$

$K_{2} = \frac{2}{K _{1}^{2}}$

$K_{2}^{2} = \frac{1}{K _{1}}$

Q. Consider the following gaseous equilibria with equilibrium constants K1​ and K2​ respectively SO2​(g)+21​O2​(g)SO3​(g) 2SO3​(g)2SO2​(g)+O2​(g) The equilibrium constants are related as

K12​=K2​1​

2K1​=K22​

K2​=K12​2​

K22​=K1​1​

Q. Consider the following gaseous equilibria with equilibrium constants $K_{1}$ and $K_{2}$ respectively $S O_{2} (g) + \frac{1}{2} O_{2} (g) S O_{3} (g)$ $2 S O_{3} (g) 2 S O_{2} (g) + O_{2} (g)$ The equilibrium constants are related as

$K_{1}^{2} = \frac{1}{K _{2}}$

$2 K_{1} = K_{2}^{2}$

$K_{2} = \frac{2}{K _{1}^{2}}$

$K_{2}^{2} = \frac{1}{K _{1}}$