Consider the following E° values E°Fe3+ /Fe2+ = 0.77 V E° Sn2+ / Sn = -0.14V Under standard conditions the potential for the reaction Sn(s) + 2Fe3+(aq) longrightarrow 2Fe2+(aq) + Sn2+(aq) is

Question

Consider the following E° values E°Fe3+ /Fe2+ = 0.77 V E° Sn2+ / Sn = -0.14V Under standard conditions the potential for the reaction Sn(s) + 2Fe3+(aq) longrightarrow 2Fe2+(aq) + Sn2+(aq) is (A) 1.68 V (B) 0.63 V (C) 0.91 V (D) 1.40 V

Tardigrade Admin · Accepted Answer

Ecell =E°RHS −E°LHS = (0.77) - (-0.14) = 0.91 V

Q. Consider the following $E^{\circ}$ values
$E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.77 V$
$E_{S n^{2 +} / S n}^{\circ} = - 0.14 V$
Under standard conditions the potential for the reaction
$S n (s) + 2 F e^{3 +} (a q) ⟶ 2 F e^{2 +} (a q) + S n^{2 +} (a q)$ is

1.68 V

0.63 V

0.91 V

1.40 V

$E_{ce ll} = E_{R H S}^{\circ} - E_{L H S}^{\circ}$
$= (0.77) - (- 0.14)$
$= 0.91 V$

Q. Consider the following E∘ values EFe3+/Fe2+∘​=0.77V ESn2+/Sn∘​=−0.14V Under standard conditions the potential for the reaction Sn(s)+2Fe3+(aq)⟶2Fe2+(aq)+Sn2+(aq) is