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Tardigrade
Question
Mathematics
Consider a sequence of 1001 terms as ( 1001 C0/1 ⋅ 2 ⋅ 3 ⋅ 4), ( 1001 C1/2 ⋅ 3 ⋅ 4 ⋅ 5), ( 1001 C2/3 ⋅ 4 ⋅ 5 ⋅ 6), ldots ( 1001 C1000/1001 ⋅ 1002 ⋅ 1003 ⋅ 1004)
Q. Consider a sequence of
1001
terms as
1
⋅
2
⋅
3
⋅
4
1001
C
0
,
2
⋅
3
⋅
4
⋅
5
1001
C
1
,
3
⋅
4
⋅
5
⋅
6
1001
C
2
,
…
1001
⋅
1002
⋅
1003
⋅
1004
1001
C
1000
130
186
Binomial Theorem
Report Error
Answer:
499
Solution:
T
r
+
1
=
(
r
+
1
)
(
r
+
2
)
(
r
+
3
)
(
r
+
4
)
1001
C
r
=
1001
⋅
1002
⋅
1003
⋅
1004
1004
C
r
+
4
is greatest when
r
=
498
∴
499
th term is greatest.