Concentrated hydrochloric acid contains 37 %HCl (by mass). The density of this solution is 1.18 g/mL. The molarity of the solution is:

Question

Concentrated hydrochloric acid contains 37 %HCl (by mass). The density of this solution is 1.18 g/mL. The molarity of the solution is: (A) 10 M (B) 12 M (C) 13 M (D) 14 M

Tardigrade Admin · Accepted Answer

Calculate the molarity of solution by using formula,
Molarity

= \frac{moles of solute}{volume of solution in litre}

Given : Mass of solute (by mass)

= 37%

d = 1.18 g / m L

Molecular mass of

H Cl = 1 + 35.5

= 36.5 g / m o l

Volume of solute

= \frac{mass of solute}{density of solution}

= \frac{100 g}{1.18 g / m o l} = 85 m o l

= 85 c m^{3} = 0.85 d m^{3}

Moles of solute

(H Cl)

= \frac{mass of solute}{molecular mass of solute}

= \frac{37 g}{36.5 g / m o l}

= 1.01 m o l

∴

molarity of solution

= \frac{1.01 m o l}{0.085 d m ^{3}}

= 12.0 m o l d m^{3}

= 12.0 M

Q. Concentrated hydrochloric acid contains 37%HCl (by mass). The density of this solution is 1.18g/mL. The molarity of the solution is:

10 M

12 M

13 M

14 M

Q. Concentrated hydrochloric acid contains $37% H Cl$ (by mass). The density of this solution is $1.18 g / m L$ . The molarity of the solution is: