Compound (A) is a carbonyl compound with lowest molecular mass that can show positive iodoform test. Molar mass of (A) compound is completely divisible by eleven. The number which comes after division is

Question

Compound (A) is a carbonyl compound with lowest molecular mass that can show positive iodoform test. Molar mass of (A) compound is completely divisible by eleven. The number which comes after division is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

CH 3 CHO molecular mass =44 / 11=4

Q. Compound $(A)$ is a carbonyl compound with lowest molecular mass that can show positive iodoform test. Molar mass of $(A)$ compound is completely divisible by eleven. The number which comes after division is

$C H_{3} C H O$ molecular mass $= 44/11 = 4$

Q. Compound (A) is a carbonyl compound with lowest molecular mass that can show positive iodoform test. Molar mass of (A) compound is completely divisible by eleven. The number which comes after division is

CH3​CHO molecular mass =44/11=4

Q. Compound $(A)$ is a carbonyl compound with lowest molecular mass that can show positive iodoform test. Molar mass of $(A)$ compound is completely divisible by eleven. The number which comes after division is

$C H_{3} C H O$ molecular mass $= 44/11 = 4$