Question

$Cl-P-Cl$ bond angles in $PC{l}_5$ molecule are

• A. $120^{\circ }$ and $90^{\circ }$
• B. $60^{\circ }$ and $90^{\circ }$
• C. $60^{\circ }$ and $120^{\circ }$
• D. $120^{\circ }$ and $30^{\circ }$

Answer 1

Answer: (A)

$Cl-P-Cl$ bond angles in $PC{l}_5$ molecule are $120^{\circ }$ and $90^{\circ }.PC{l}_5$, having $s{p}^{3}d$ hybridised $P$ atom (trigonal bipyramidal geometry) has two types of bonds; axial and equatorial. These two types of bond have different bond lengths $1,2,3$ - equatorial bonds and $4,5$ axial bonds