Circles x2 + y2 - 2x - 4y = 0 and x2 + y2 -8 y -4 = 0

Question

Circles x2 + y2 - 2x - 4y = 0 and x2 + y2 -8 y -4 = 0  (A) touch each other externally (B) touch each other internally (C) do not touch each other (D) none of these.

Tardigrade Admin · Accepted Answer

Correct answer is (b) touch each other internally

Q. Circles x2+y2−2x−4y=0 and x2+y2−8y−4=0

touch each other externally

touch each other internally

do not touch each other

none of these.

Correct answer is (b) touch each other internally

Q. Circles $x^{2} + y^{2} - 2 x - 4 y = 0$ and $x^{2} + y^{2} - 8 y - 4 = 0$