Chloroform, CHCl 3, boils at 61.7° C. If the Kb for chloroform is 3.63° C / molal, what is the boiling point of a solution of 15.0 kg of CHCl 3 and 0.616 kg of acenaphthalene, C 12 H 10 ?

Question

Chloroform, CHCl 3, boils at 61.7° C. If the Kb for chloroform is 3.63° C / molal, what is the boiling point of a solution of 15.0 kg of CHCl 3 and 0.616 kg of acenaphthalene, C 12 H 10 ? (A) 61.9 (B) 62.0 (C) 52.2 (D) 62.67

Tardigrade Admin · Accepted Answer

Δb=Kb ⋅ m ⇒ 3.63 × (0.616 / 154/15) × 1000 Tb =61 ⋅ 7+0 ⋅ 968 =62.67° C

Q. Chloroform, $C H C l_{3}$ , boils at $61. 7^{\circ} C$ . If the $K_{b}$ for chloroform is $3.6 3^{\circ} C / m o l a l$ , what is the boiling point of a solution of $15.0 k g$ of $C H C l_{3}$ and $0.616 k g$ of acenaphthalene, $C_{12} H_{10}$ ?

61.9

62.0

52.2

62.67

$Δ_{b} = K_{b} \cdot m$
$\Rightarrow 3.63 \times \frac{0.616/154}{15} \times 1000$
$T_{b} = 61 \cdot 7 + 0 \cdot 968$
$= 62.6 7^{\circ} C$

Q. Chloroform, CHCl3​, boils at 61.7∘C. If the Kb​ for chloroform is 3.63∘C/molal, what is the boiling point of a solution of 15.0kg of CHCl3​ and 0.616kg of acenaphthalene, C12​H10​ ?