CH 3 CONH 2, Br 2 KOH give CH 3 NH 2 as the product. The intermediates of the reaction are (a)CH 3- overset underset||OC - NHBr (b)CH 3- N = C = O (c)CH 3 NHBr (d) The correct answer is:

Question

CH 3 CONH 2, Br 2 KOH give CH 3 NH 2 as the product. The intermediates of the reaction are (a)CH 3- overset underset||OC - NHBr (b)CH 3- N = C = O (c)CH 3 NHBr (d)<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a413f609d91d27f4ba1551a87f7a61e0-.png" /> The correct answer is: (A) a, b (B) a, c (C) b, d (D) c, d

Tardigrade Admin · Accepted Answer

In hoffmann's bromamide degradation reaction. CH3 - overset underset||OC- NH2 ->[NaOH/Br2][-H2O, - NaBr] underset text(N - Bromamide) IntermediateCH3 - overset underset||OC - NHBr <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/5fd6b23c0140a993c772c48acf6073dd-.png" />

Q. $C H_{3} CON H_{2}, B r_{2} & K O H$ give $C H_{3} N H_{2}$ as the product. The intermediates of the reaction are
(a) $C H_{3} - C ∣∣ O - N H B r$
(b) $C H_{3} - N = C = O$
(c) $C H_{3} N H B r$
(d)
The correct answer is:

a, b

a, c

b, d

c, d

In hoffmann's bromamide degradation reaction.
$C H_{3} - C ∣∣ O - N H_{2} NaOH / Br X_{2} - H X_{2} O, - NaBr (N - Bromamide) Intermediate C H_{3} - C ∣∣ O - N H B r$

Q. CH3​CONH2​,Br2​&KOH give CH3​NH2​ as the product. The intermediates of the reaction are (a)CH3​−C∣∣O​−NHBr (b)CH3​−N=C=O (c)CH3​NHBr (d) The correct answer is: