CH 3 C ≡ CCH 3 xrightarrowH 2 / P t A xrightarrowD2 / P t B The compounds A and B, respectively are

Question

CH 3 C ≡ CCH 3 xrightarrowH 2 / P t A xrightarrowD2 / P t B The compounds A and B, respectively are (A) cis-butene-2 and rac-2, 3-dideuterobutane (B) trans-butene-2 and rac-2, 3-dideuterobutane (C) cis-butene-2 and meso-2, 3-dideuterobutane (D) trans-butene-2 and meso-2, 3-dideuterobutane

Tardigrade Admin · Accepted Answer

Catalytic hydrogenation of alkynes gives cis-alkene which in turn adds deuterium atoms in presence of H2 again in cis-manner forming meso-2, 3-dideuterobutane.

Q. $C H_{3} C \equiv CC H_{3} H 2/ Pt A D_{2} / Pt B$
The compounds $A$ and $B$ , respectively are

cis-butene-2 and rac-2, 3-dideuterobutane

trans-butene-2 and rac-2, 3-dideuterobutane

cis-butene-2 and meso-2, 3-dideuterobutane

trans-butene-2 and meso-2, 3-dideuterobutane

Catalytic hydrogenation of alkynes gives cis-alkene which in turn adds deuterium atoms in presence of $H_{2}$ again in cis-manner forming meso- $2, 3$ -dideuterobutane.

Q. CH3​C≡CCH3​H2/Pt​AD2​/Pt​B The compounds A and B, respectively are