Capacitor C3 in the circuit is a variable capacitor (its capacitance can be varied). Graph is plotted between potential difference V1 (across capacitor C1 ) versus C3. Electric potential V1 approaches on asymptote of 10 V as C3 arrow ∞. Then C1 / C2 has value

Question

Capacitor C3 in the circuit is a variable capacitor (its capacitance can be varied). Graph is plotted between potential difference V1 (across capacitor C1 ) versus C3. Electric potential V1 approaches on asymptote of 10 V as C3 arrow ∞. Then C1 / C2 has value (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

For C3 arrow ∞:

⇒ V=10 V ...(i) For C3 = 0

Now, V=(Q/C) ∴ (2/8)=(C2/C1) C1=4 C2

Q. Capacitor C3​ in the circuit is a variable capacitor (its capacitance can be varied). Graph is plotted between potential difference V1​ (across capacitor C1​ ) versus C3​. Electric potential V1​ approaches on asymptote of 10V as C3​→∞. Then C1​/C2​ has value

For C3​→∞ : ⇒V=10V...(i) For C3​=0 Now, V=CQ​ ∴82​=C1​C2​​ C1​=4C2​

For $C_{3} \to \infty$ :

$\Rightarrow V = 10 V ... (i)$
For $C_{3} = 0$

Now, $V = \frac{Q}{C}$
$∴ \frac{2}{8} = \frac{C _{2}}{C _{1}}$
$C_{1} = 4 C_{2}$