Calculate the Z text eff of 39 text th electron of ytrrium.

Question

Calculate the Z text eff of 39 text th electron of ytrrium. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

39 Y:(1 s2)(2 s2 2 p6)(3 s2 3 p6)(3 d10)(4 s2 4 p6)(4 d),(5 s2) 39 text th electron of Y is present in 4 d-subshell Z text eff =Z-σ=39-σ s4 d=36 × 1+0 × 0.35 ⇒ 36 ∴ Z text eff =3

Q. Calculate the $Z_{eff}$ of $3 9^{th}$ electron of ytrrium.

$_{39} Y : (1 s^{2}) (2 s^{2} 2 p^{6}) (3 s^{2} 3 p^{6}) (3 d^{10}) (4 s^{2} 4 p^{6}) (4 d), (5 s^{2})$
$3 9^{th}$ electron of $Y$ is present in $4 d$ -subshell
$Z_{eff} = Z - σ = 39 - σ$
$s_{4 d} = 36 \times 1 + 0 \times 0.35 \Rightarrow 36$
$∴ Z_{eff} = 3$

Q. Calculate the Zeff ​ of 39th electron of ytrrium.

39​Y:(1s2)(2s22p6)(3s23p6)(3d10)(4s24p6)(4d),(5s2) 39th electron of Y is present in 4d-subshell Zeff ​=Z−σ=39−σ s4d​=36×1+0×0.35⇒36 ∴Zeff ​=3

Q. Calculate the $Z_{eff}$ of $3 9^{th}$ electron of ytrrium.

$_{39} Y : (1 s^{2}) (2 s^{2} 2 p^{6}) (3 s^{2} 3 p^{6}) (3 d^{10}) (4 s^{2} 4 p^{6}) (4 d), (5 s^{2})$
$3 9^{th}$ electron of $Y$ is present in $4 d$ -subshell
$Z_{eff} = Z - σ = 39 - σ$
$s_{4 d} = 36 \times 1 + 0 \times 0.35 \Rightarrow 36$
$∴ Z_{eff} = 3$