Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Calculate the value of equilibrium constant of the reaction at text22 text7oC , if the Δ Go for the reaction X+Yleftharpoons Z is - 4.606 kcal . (.R= text2.0cal.mol- 1K- 1.)
Q. Calculate the value of equilibrium constant of the reaction at
22
7
o
C
, if the
Δ
G
o
for the reaction
X
+
Y
⇌
Z
is - 4.606 kcal .
(
R
=
2.0
c
a
l
.
m
o
l
−
1
K
−
1
)
1591
204
NTA Abhyas
NTA Abhyas 2020
Equilibrium
Report Error
A
100
58%
B
10
11%
C
2
16%
D
0.01
14%
Solution:
Δ
G
o
=
−
2.303
RT
log
K
−
4.606
=
−
2.303
×
0.002
×
500
log
K
log
K
=
2
,
K
=
100
.