Calculate the pH of a solution obtain by mixing text10 textml of text1 textN sodium acetate and text50 textml of text2 textN acetic acid (.Ka=1.8× 10- 5.),

Question

Calculate the pH of a solution obtain by mixing text10 textml of text1 textN sodium acetate and text50 textml of text2 textN acetic acid (.Ka=1.8× 10- 5.), (A) 3.74 (B) 5 (C) 6 (D) 7

Tardigrade Admin · Accepted Answer

pH=pKa+log([. S a l t ]./[. A c i d ].) pH=-log(.1.8× 10- 5.)+log([. 10 ]./[. 100 ].) =-log1.8+5+log10- 1 =-0.2553+5-1=3.7447

Q. Calculate the pH of a solution obtain by mixing $10 ml$ of $1 N$ sodium acetate and $50 ml$ of $2 N$ acetic acid $(K_{a} = 1.8 \times 1 0^{- 5}),$

3.74

5

6

7

$p H = p K_{a} + l o g \frac{[ S a lt ]}{[ A c i d ]}$
$p H = - l o g (1.8 \times 1 0^{- 5}) + l o g \frac{[ 10 ]}{[ 100 ]}$
$= - l o g 1.8 + 5 + l o g 1 0^{- 1}$
$= - 0.2553 + 5 - 1 = 3.7447$

Q. Calculate the pH of a solution obtain by mixing 10ml of 1N sodium acetate and 50ml of 2N acetic acid (Ka​=1.8×10−5),

3.74

5

6

7

pH=pKa​+log[Acid][Salt]​ pH=−log(1.8×10−5)+log[100][10]​ =−log1.8+5+log10−1 =−0.2553+5−1=3.7447

Q. Calculate the pH of a solution obtain by mixing $10 ml$ of $1 N$ sodium acetate and $50 ml$ of $2 N$ acetic acid $(K_{a} = 1.8 \times 1 0^{- 5}),$

$p H = p K_{a} + l o g \frac{[ S a lt ]}{[ A c i d ]}$
$p H = - l o g (1.8 \times 1 0^{- 5}) + l o g \frac{[ 10 ]}{[ 100 ]}$
$= - l o g 1.8 + 5 + l o g 1 0^{- 1}$
$= - 0.2553 + 5 - 1 = 3.7447$