Calculate the energy required (in eV ) to remove both the electrons of He atom, if the binding energy of an electron in the ground state of He is equal to 24.6eV .

Question

Calculate the energy required (in eV ) to remove both the electrons of He atom, if the binding energy of an electron in the ground state of He is equal to 24.6eV . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

The energy needed to remove one electron from the ground state of

He = 24.6 e V

As the

H e^{+}

is now hydrogen-like, Ionisation energy

= \frac{13.6 Z ^{2}}{n ^{2}} e V

= \frac{13.6 \times 2 ^{2}}{1 ^{2}} e V

= 54.4 e V

∴

To remove both the electrons, energy needed

= (54.4 + 24.6) e V = 79 e V

Q. Calculate the energy required (in eV ) to remove both the electrons of He atom, if the binding energy of an electron in the ground state of He is equal to 24.6eV .

The energy needed to remove one electron from the ground state of He=24.6eV As the He+ is now hydrogen-like, Ionisation energy =n213.6Z2​eV =1213.6×22​eV =54.4eV ∴ To remove both the electrons, energy needed =(54.4+24.6)eV=79eV

Q. Calculate the energy required (in $e V$ ) to remove both the electrons of $He$ atom, if the binding energy of an electron in the ground state of $He$ is equal to $24.6 e V$ .