Calculate the cell constant if the specific conductance of a solution is 0.2 ohm- 1cm- 1 and its conductivity is 0.04 ohm- 1 .

Question

Calculate the cell constant if the specific conductance of a solution is 0.2 ohm- 1cm- 1 and its conductivity is 0.04 ohm- 1 . (A) 1 cm- 1 (B) 0 cm- 1 (C) 5 cm- 1 (D) 0.2 cm- 1

Tardigrade Admin · Accepted Answer

K=C× Cell constant Cell constant=(K/C) =(0.2/0.04)=5 cm- 1

Q. Calculate the cell constant if the specific conductance of a solution is 0.2 $o h m^{- 1} c m^{- 1}$ and its conductivity is 0.04 $o h m^{- 1}$ .

1 $c m^{- 1}$

0 $c m^{- 1}$

5 $c m^{- 1}$

0.2 $c m^{- 1}$

$K = C \times C e ll co n s t an t C e ll co n s t an t = \frac{K}{C}$

$= \frac{0.2}{0.04} = 5 c m^{- 1}$

Q. Calculate the cell constant if the specific conductance of a solution is 0.2 ohm−1cm−1 and its conductivity is 0.04 ohm−1 .

1 cm−1

0 cm−1

5 cm−1

0.2 cm−1