Calculate the acceleration due to gravity on the surface of a pulsar of mass M = 1.98 × 1030 kg and radius R = 12 km rotating with time period T = 0.041 s. (G = 6.67 × 10-11MKS)

Question

Calculate the acceleration due to gravity on the surface of a pulsar of mass M = 1.98 × 1030 kg and radius R = 12 km rotating with time period T = 0.041 s. (G = 6.67 × 10-11MKS)  (A)  9.2× 1011 m/s2  (B)  8.15× 1011 m/s2  (C)  7.32× 1011 m/s2  (D)  6.98× 1011 m/s2

Tardigrade Admin · Accepted Answer

The acceleration due to gravity g = (GM/R2) = (6.67× 10-11× 1.98 × 1030/12000× 12000) = 9.2 × 1011 m/s2

Q. Calculate the acceleration due to gravity on the surface of a pulsar of mass $M = 1.98 \times 1 0^{30} k g$ and radius $R = 12 km$ rotating with time period $T = 0.041 s . (G = 6.67 \times 1 0^{- 11} M K S)$

$9.2 \times 1 0^{11} m / s^{2}$

$8.15 \times 1 0^{11} m / s^{2}$

$7.32 \times 1 0^{11} m / s^{2}$

$6.98 \times 1 0^{11} m / s^{2}$

The acceleration due to gravity
$g = \frac{GM}{R ^{2}}$
$= \frac{6.67 \times 1 0 ^{- 11} \times 1.98 \times 1 0 ^{30}}{12000 \times 12000}$
$= 9.2 \times 1 0^{11} m / s^{2}$

Q. Calculate the acceleration due to gravity on the surface of a pulsar of mass M=1.98×1030kg and radius R=12km rotating with time period T=0.041s.(G=6.67×10−11MKS)

9.2×1011m/s2

8.15×1011m/s2

7.32×1011m/s2

6.98×1011m/s2