Calculate maximum kinetic energy of electrons emitted from a photo sensitive surface of work function 3.2 eV for the incident radiation of wavelength 300 nm :

Question

Calculate maximum kinetic energy of electrons emitted from a photo sensitive surface of work function 3.2 eV for the incident radiation of wavelength 300 nm : (A) 0.1 eV (B) 0.2 eV (C) 0.5 eV (D) 0.925 eV

Tardigrade Admin · Accepted Answer

E k =( hc /λ)-φ o E k =((6.6 × 10-34 × 3 × 108/300 × 10-9 × 1.6 × 10-19)-3.2) eV =4.125-3.2=0.925 eV

Q. Calculate maximum kinetic energy of electrons emitted from a photo sensitive surface of work function $3.2 e V$ for the incident radiation of wavelength $300 nm$ :

$0.1 e V$

$0.2 e V$

$0.5 e V$

$0.925 e V$

$E_{k} = \frac{h c}{λ} - ϕ_{o}$
$E_{k} = (\frac{6.6 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{300 \times 1 0 ^{- 9} \times 1.6 \times 1 0 ^{- 19}} - 3.2) e V$
$= 4.125 - 3.2 = 0.925 e V$

Q. Calculate maximum kinetic energy of electrons emitted from a photo sensitive surface of work function 3.2eV for the incident radiation of wavelength 300nm :

0.1eV

0.2eV

0.5eV

0.925eV