Question

By increasing temperature of a gas by $6^{\circ }C$ its pressure increases by $0.4\%$, at constant volume. Then initial temperature of gas is

• A. 1000 K
• B. 1500 K
• C. 2000 K
• D. 750 K

Answer 1

Answer: (B)

$\frac{P_2}{P_1}=\frac{T_2}{T_1}$
$T_1=T$
$T_2=T+6$
$\frac{P_2}{P_1}-1=\frac{T_2}{T_1}-1$
$\frac{P_2-P_1}{P_1}\times 100=\left(\frac{T+6}{T}-1\right)100$
$0.4=\frac{600}{T}\Rightarrow T=1500K$