Balmer's formula for spectral series of hydrogen is

Question

Balmer's formula for spectral series of hydrogen is (A) (1/λ)=R((1/4)-(1/n2)) (B) (1/λ)=R((1/2)-(1/n2)) (C) (1/λ)=R((1/9)-(1/n2)) (D) (1/λ)=R((1/12)-(1/n2))

Tardigrade Admin · Accepted Answer

Correct answer is (a) (1/λ)=R((1/4)-(1/n2))

Q. Balmer's formula for spectral series of hydrogen is

$\frac{1}{λ} = R (\frac{1}{4} - \frac{1}{n ^{2}})$

$\frac{1}{λ} = R (\frac{1}{2} - \frac{1}{n ^{2}})$

$\frac{1}{λ} = R (\frac{1}{9} - \frac{1}{n ^{2}})$

$\frac{1}{λ} = R (\frac{1}{1 ^{2}} - \frac{1}{n ^{2}})$

Correct answer is (a) $\frac{1}{λ} = R (\frac{1}{4} - \frac{1}{n ^{2}})$

Q. Balmer's formula for spectral series of hydrogen is

λ1​=R(41​−n21​)

λ1​=R(21​−n21​)

λ1​=R(91​−n21​)

λ1​=R(121​−n21​)

Correct answer is (a) λ1​=R(41​−n21​)

$\frac{1}{λ} = R (\frac{1}{4} - \frac{1}{n ^{2}})$

$\frac{1}{λ} = R (\frac{1}{2} - \frac{1}{n ^{2}})$

$\frac{1}{λ} = R (\frac{1}{9} - \frac{1}{n ^{2}})$

$\frac{1}{λ} = R (\frac{1}{1 ^{2}} - \frac{1}{n ^{2}})$

Correct answer is (a) $\frac{1}{λ} = R (\frac{1}{4} - \frac{1}{n ^{2}})$