Avogadro's number is the number of molecules present in :

Question

Avogadro's number is the number of molecules present in : (A) 1 L of molecule (B) 1 g of molecules (C) gram molecular mass (D) 1 g atom of molecules

Tardigrade Admin · Accepted Answer

Avogardo?s number (6.023× 1023) is the number of molecules present in 12 g of C12 isotope of carbon 1 mole of any/substance (at STP) contains 6.023× 1023 molecules 1 mole = gram/molecular mass of a substance =32g O2 =2 g H2 etc.

Q. Avogadro's number is the number of molecules present in :

1 L of molecule

1 g of molecules

gram molecular mass

1 g atom of molecules

Avogardo?s number $(6.023 \times 10^{23})$ is the number of molecules present in 12 g of $C^{12}$ isotope of carbon 1 mole of any/substance (at STP) contains $6.023 \times 10^{23}$ molecules 1 mole = gram/molecular mass of a substance $= 32 g O_{2}$ $= 2 g H_{2}$ etc.

Q. Avogadro's number is the number of molecules present in :

1 L of molecule

1 g of molecules

gram molecular mass

1 g atom of molecules

Avogardo?s number (6.023×1023) is the number of molecules present in 12 g of C12 isotope of carbon 1 mole of any/substance (at STP) contains 6.023×1023 molecules 1 mole = gram/molecular mass of a substance =32gO2​ =2gH2​ etc.

Avogardo?s number $(6.023 \times 10^{23})$ is the number of molecules present in 12 g of $C^{12}$ isotope of carbon 1 mole of any/substance (at STP) contains $6.023 \times 10^{23}$ molecules 1 mole = gram/molecular mass of a substance $= 32 g O_{2}$ $= 2 g H_{2}$ etc.