At STP, 5.6 litre of a gas weighs 60 g . The vapour density of gas is -

Question

At STP, 5.6 litre of a gas weighs 60 g . The vapour density of gas is - (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

5.6 lit gas weight = 60 gm 22.4 lit gas weight = (60/5.6)× 22.4 gm = 240 text gm (. textmolecular weight of gas .) textVapour density = ( textM texto textl texte textc textu textl texta textr text weight/2) = 120

Q. At STP, 5.6 litre of a gas weighs $60 g$ . The vapour density of gas is -

$5.6 l i t$ gas weight $= 60 g m$

$22.4 l i t$ gas weight $= \frac{60}{5.6} \times 22.4 g m$

$= 240 gm (molecular weight of gas)$

$Vapour density = \frac{M o l e c u l a r weight}{2} = 120$

Q. At STP, 5.6 litre of a gas weighs 60g . The vapour density of gas is -

5.6lit gas weight =60gm 22.4lit gas weight =5.660​×22.4gm =240 gm (molecular weight of gas) Vapour density=2Molecular weight​=120

Q. At STP, 5.6 litre of a gas weighs $60 g$ . The vapour density of gas is -

$5.6 l i t$ gas weight $= 60 g m$

$22.4 l i t$ gas weight $= \frac{60}{5.6} \times 22.4 g m$

$= 240 gm (molecular weight of gas)$

$Vapour density = \frac{M o l e c u l a r weight}{2} = 120$