At a certain place, the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.50 oerested. The earth's total magnetic field (in oerested) is

Question

At a certain place, the angle of dip is 30° and the horizontal component of earth's magnetic field is 0.50 oerested. The earth's total magnetic field (in oerested) is (A) √3 (B) 1 (C) (1/√3) (D) (1/2)

Tardigrade Admin · Accepted Answer

B =( H / cos θ)=(0.50/ cos 30°)=(0.50 × 2/√3)=1 / √3

Q. At a certain place, the angle of dip is $3 0^{\circ}$ and the horizontal component of earth's magnetic field is $0.50$ oerested. The earth's total magnetic field (in oerested) is

$3$

1

$\frac{1}{3}$

$\frac{1}{2}$

$B = \frac{H}{c o s θ} = \frac{0.50}{c o s 3 0 ^{\circ}} = \frac{0.50 \times 2}{3} = 1/ 3$

Q. At a certain place, the angle of dip is 30∘ and the horizontal component of earth's magnetic field is 0.50 oerested. The earth's total magnetic field (in oerested) is

3​

1

3​1​

21​

B=cosθH​=cos30∘0.50​=3​0.50×2​=1/3​

Q. At a certain place, the angle of dip is $3 0^{\circ}$ and the horizontal component of earth's magnetic field is $0.50$ oerested. The earth's total magnetic field (in oerested) is

$3$

$\frac{1}{3}$

$\frac{1}{2}$

$B = \frac{H}{c o s θ} = \frac{0.50}{c o s 3 0 ^{\circ}} = \frac{0.50 \times 2}{3} = 1/ 3$