At 25° C and 760 mm of Hg pressure, a gas occupies 600 mL volume. What will be its pressure at a height where temperature is 10° C and volume of the gas is 640 mL ?

Question

At 25° C and 760 mm of Hg pressure, a gas occupies 600 mL volume. What will be its pressure at a height where temperature is 10° C and volume of the gas is 640 mL ? (A) 677 mm Hg (B) 600 mm Hg (C) 700 mm Hg (D) 752 mm Hg

Tardigrade Admin · Accepted Answer

p1=760 mm Hg , V1=600 mL T1=25+273=298 K V2=640 mL and T2=10+273=283 K According to combined gas law, (p1 V1/T1) =(p2 V2/T2) ⇒ p2=(p1 V1 T2/T1 V2) ⇒ p2=((760 mm Hg ) ×(600 mL ) ×(283 K )/(640 mL ) ×(298 K )) =676.6 mm Hg ≈ 677 mm Hg

Q. At $2 5^{\circ} C$ and $760 mm$ of $H g$ pressure, a gas occupies $600 m L$ volume. What will be its pressure at a height where temperature is $1 0^{\circ} C$ and volume of the gas is $640 m L$ ?

$677 mm H g$

$600 mm H g$

$700 mm H g$

$752 mm H g$

Q. At 25∘C and 760mm of Hg pressure, a gas occupies 600mL volume. What will be its pressure at a height where temperature is 10∘C and volume of the gas is 640mL ?

677mmHg

600mmHg

700mmHg

752mmHg

p1​=760mmHg, V1​=600mL T1​=25+273=298K V2​=640mL and T2​=10+273=283K According to combined gas law, T1​p1​V1​​=T2​p2​V2​​ ⇒p2​=T1​V2​p1​V1​T2​​ ⇒p2​=(640mL)×(298K)(760mmHg)×(600mL)×(283K)​ =676.6mmHg ≈677mmHg

Q. At $2 5^{\circ} C$ and $760 mm$ of $H g$ pressure, a gas occupies $600 m L$ volume. What will be its pressure at a height where temperature is $1 0^{\circ} C$ and volume of the gas is $640 m L$ ?

$677 mm H g$

$600 mm H g$

$700 mm H g$

$752 mm H g$