At 25°C and 760 mm Hg pressure a gas occupies 600 mL volume. What will be its pressure at a height where temperature is 10°C and volume of the gas is 640 mL?

Question

At 25°C and 760 mm Hg pressure a gas occupies 600 mL volume. What will be its pressure at a height where temperature is 10°C and volume of the gas is 640 mL? (A) 576.6 mm Hg (B) 676.6 mm Hg (C) 777.7 mm Hg (D) 667.8 mm Hg

Tardigrade Admin · Accepted Answer

P1 = 760 mm Hg, V1 = 600 mL T1 = 25 + 273 = 298 K V2 = 640 mL and T2 = 10 + 273 = 283 K According to combined gas law, (P1V1/T1) = (P2V2/T2) ⇒ P2 = (P1V1T2/T1V2) ⇒ P2 = (760(mm Hg) ×(600 mL) ×(283 K)/(640 mL) ×(298 K)) = 676.6 mm Hg

Q. At $2 5^{\circ} C$ and $760 mm H g$ pressure a gas occupies $600 m L$ volume. What will be its pressure at a height where temperature is $1 0^{\circ} C$ and volume of the gas is $640 m L$ ?

$576.6$ mm Hg

$676.6$ mm Hg

$777.7$ mm Hg

$667.8$ mm Hg

Q. At 25∘C and 760mmHg pressure a gas occupies 600mL volume. What will be its pressure at a height where temperature is 10∘C and volume of the gas is 640mL?

576.6 mm Hg

676.6 mm Hg

777.7 mm Hg

667.8 mm Hg

P1​=760 mm Hg, V1​=600mL T1​=25+273=298K V2​=640 mL and T2​=10+273=283K According to combined gas law, T1​P1​V1​​=T2​P2​V2​​ ⇒P2​=T1​V2​P1​V1​T2​​ ⇒P2​=(640mL)×(298K)760(mmHg)×(600mL)×(283K)​ =676.6 mm Hg

Q. At $2 5^{\circ} C$ and $760 mm H g$ pressure a gas occupies $600 m L$ volume. What will be its pressure at a height where temperature is $1 0^{\circ} C$ and volume of the gas is $640 m L$ ?

$576.6$ mm Hg

$676.6$ mm Hg

$777.7$ mm Hg

$667.8$ mm Hg