Question

At $10^{\circ }C$ the value of the density of a fixed mass of an ideal gas divided by it pressure is $x$. At $110^{\circ }C$ this ratio is

• A. $\frac{10}{110}x$
• B. $\frac{283}{383}x$
• C. $x$
• D. $\frac{383}{283}x$

Answer 1

Answer: (B)

Mass of the gas $=m$.
At a fixed temperature and pressure, volume is fixed.
Density of the gas $\rho =\frac{m}{V}$
$\Rightarrow \frac{m}{V.P}=\frac{m}{nRT}=x$
$\therefore \times T=$ constant.
At $10^{\circ }C$ i.e., $283K,\times T=\times 283K$
At $110^{\circ }C,xT=x^{\prime }383K$
$\Rightarrow x^{\prime }=\frac{283}{383}x$