Assuming human pupil to have a radius of 0.25 cm and a comfortable viewing distance of 25 cm, the minimum separation between two objects that human eye can resolve at 500 nm wavelength is

Question

Assuming human pupil to have a radius of 0.25 cm and a comfortable viewing distance of 25 cm, the minimum separation between two objects that human eye can resolve at 500 nm wavelength is (A) 30 μ m (B) 1 μ m (C) 100 μ m (D) 300 μ m

Tardigrade Admin · Accepted Answer

y=1.22 (λ D/d)=(500 × 10-9 × 25 × 10-2/2 × 0.25 × 10-2) ⇒ y=30 μ m

Q. Assuming human pupil to have a radius of $0.25 c m$ and a comfortable viewing distance of $25 c m$ , the minimum separation between two objects that human eye can resolve at $500 nm$ wavelength is

$30 μ m$

$1 μ m$

$100 μ m$

$300 μ m$

$y = 1.22 \frac{λ D}{d} = \frac{500 \times 1 0 ^{- 9} \times 25 \times 1 0 ^{- 2}}{2 \times 0.25 \times 1 0 ^{- 2}}$
$\Rightarrow y = 30 μ m$

Q. Assuming human pupil to have a radius of 0.25cm and a comfortable viewing distance of 25cm, the minimum separation between two objects that human eye can resolve at 500nm wavelength is

30μm

1μm

100μm

300μm