Assume that 3.13 ≤ π ≤ 3.15. The integer closest to the value of sin -1( sin 1 cos 4+ cos 1 sin 4 ), where 1 and 4 appearing in sin and cos are given in radians, is:

Question

Assume that 3.13 ≤ π ≤ 3.15. The integer closest to the value of sin -1( sin 1 cos 4+ cos 1 sin 4 ), where 1 and 4 appearing in sin and cos are given in radians, is: (A) -1 (B) 1 (C) 3 (D) 5

Tardigrade Admin · Accepted Answer

θ= sin -1( sin 5) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/c73b7ef14fd9a2e46c57f6304a652c0b-.png" /> =-(2 π-5) =5-2 π ≈-1.26 (as π ≈ 3.13)

Q. Assume that $3.13 \leq π \leq 3.15$ . The integer closest to the value of $sin^{- 1} (sin 1 cos 4 + cos 1$ $sin 4$ ), where 1 and 4 appearing in $sin$ and $cos$ are given in radians, is:

-1

1

3

5

$θ = sin^{- 1} (sin 5)$

$= - (2 π - 5)$
$= 5 - 2 π \approx - 1.26$ (as $π \approx 3.13)$

Q. Assume that 3.13≤π≤3.15. The integer closest to the value of sin−1(sin1cos4+cos1 sin4 ), where 1 and 4 appearing in sin and cos are given in radians, is:

-1

1

3

5

θ=sin−1(sin5) =−(2π−5) =5−2π≈−1.26 (as π≈3.13)

Q. Assume that $3.13 \leq π \leq 3.15$ . The integer closest to the value of $sin^{- 1} (sin 1 cos 4 + cos 1$ $sin 4$ ), where 1 and 4 appearing in $sin$ and $cos$ are given in radians, is:

$θ = sin^{- 1} (sin 5)$

$= - (2 π - 5)$
$= 5 - 2 π \approx - 1.26$ (as $π \approx 3.13)$