Assume that 2 × 10-17 J of light energy is needed by the interior of the human eye to see an object. How many photons of yellow light with λ=595.2 nm are needed to generate this minimum energy?

Question

Assume that 2 × 10-17 J of light energy is needed by the interior of the human eye to see an object. How many photons of yellow light with λ=595.2 nm are needed to generate this minimum energy? (A) 6 (B) 30 (C) 45 (D) 60

Tardigrade Admin · Accepted Answer

E=n (h c/λ) ⇒ 2 × 10-17 =n × (6.626 × 10-34 × 3 × 108/595.2 × 10-9) ⇒ n=60

Q. Assume that $2 \times 1 0^{- 17} J$ of light energy is needed by the interior of the human eye to see an object. How many photons of yellow light with $λ = 595.2 nm$ are needed to generate this minimum energy?

6

30

45

60

$E = n \frac{h c}{λ}$
$\Rightarrow 2 \times 1 0^{- 17}$
$= n \times \frac{6.626 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{595.2 \times 1 0 ^{- 9}}$
$\Rightarrow n = 60$

Q. Assume that 2×10−17J of light energy is needed by the interior of the human eye to see an object. How many photons of yellow light with λ=595.2nm are needed to generate this minimum energy?

6

30

45

60

E=nλhc​ ⇒2×10−17 =n×595.2×10−96.626×10−34×3×108​ ⇒n=60

Q. Assume that $2 \times 1 0^{- 17} J$ of light energy is needed by the interior of the human eye to see an object. How many photons of yellow light with $λ = 595.2 nm$ are needed to generate this minimum energy?

$E = n \frac{h c}{λ}$
$\Rightarrow 2 \times 1 0^{- 17}$
$= n \times \frac{6.626 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{595.2 \times 1 0 ^{- 9}}$
$\Rightarrow n = 60$