Question

Assertion (A) Glucose on acetylation gives pentaacetate.
Reason (R) It contains five $-OH$ group.

• A. Both $A$ and $R$ are correct; $R$ is the correct explanation of $A$.
• B. Both $A$ and $R$ are correct; $R$ is not the correct explanation of $A$.
• C. $A$ is correct but $R$ is incorrect.
• D. $R$ is correct but $A$ is incorrect.

Answer 1

Answer: (A)

Acetylation of glucose with acetic anhydride gives glucosepentaacetate which confirms the presence of five $-OH$ groups. Since, it exists as a stable compound, five $-OH$ groups should be attached to different carbon atoms.