Assertion: A deuteron and an a-particle are placed in an electric field. If F1 and F2 be the forces acting on them and a1 and a2 be their accelerations respectively then, a1 = a2. Reason: Forces will be same in electric field.

Question

Assertion: A deuteron and an a-particle are placed in an electric field. If F1 and F2 be the forces acting on them and a1 and a2 be their accelerations respectively then, a1 = a2. Reason: Forces will be same in electric field. (A) If both Assertion and Reason are correct and Reason is the correct explanation of Assertion. (B) If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion. (C) If Assertion is correct but Reason is incorrect. (D) If both the Assertion and Reason are incorrect.

Tardigrade Admin · Accepted Answer

q d = e , m d =2 m p =2 m q α=2 e , m α=4 m p =4 m F 1= F α= eE , F 2= F α=2 e E ≠ F 1 Further, a 1=( F 1/2 m )=( eE /2 m ) anda 2=( F 2/2 m )=(2 e E /4 m )=( eE /2 m )= a 1

Q. Assertion : A deuteron and an a-particle are placed in an electric field. If $F_{1}$ and $F_{2}$ be the forces acting on them and $a_{1}$ and $a_{2}$ be their accelerations respectively then, $a_{1} = a_{2}$ .
Reason : Forces will be same in electric field.

If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.

If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.

If Assertion is correct but Reason is incorrect.

If both the Assertion and Reason are incorrect.

$q_{d} = e, m_{d} = 2 m_{p} = 2 m$
$q_{α} = 2 e, m_{α} = 4 m_{p} = 4 m$
$F_{1} = F_{α} = e E, F_{2} = F_{α} = 2 e E \neq = F_{1}$
Further, $a_{1} = \frac{F _{1}}{2 m} = \frac{e E}{2 m}$
anda $_{2} = \frac{F _{2}}{2 m} = \frac{2 e E}{4 m} = \frac{e E}{2 m} = a_{1}$

Q. Assertion : A deuteron and an a-particle are placed in an electric field. If F1​ and F2​ be the forces acting on them and a1​ and a2​ be their accelerations respectively then, a1​=a2​. Reason : Forces will be same in electric field.