As shown in the figure, a very thin sheet of aluminium is placed in between the plates of the condenser. Then the capacity

Question

As shown in the figure, a very thin sheet of aluminium is placed in between the plates of the condenser. Then the capacity (A) will increase (B) will decrease (C) remain unchanged (D) may increase or decrease

Tardigrade Admin · Accepted Answer

Since aluminium is a metal, therefore field inside this will be zero. Hence it would not affect the field in between the two plates, so capacity =(q/V)=(q/E d) remains unchanged.

Q. As shown in the figure, a very thin sheet of aluminium is placed in between the plates of the condenser. Then the capacity

will increase

will decrease

remain unchanged

may increase or decrease

Since aluminium is a metal, therefore field inside this will be zero. Hence it would not affect the field in between the two plates, so capacity $= \frac{q}{V} = \frac{q}{E d}$ remains unchanged.

Q. As shown in the figure, a very thin sheet of aluminium is placed in between the plates of the condenser. Then the capacity

will increase

will decrease

remain unchanged

may increase or decrease

Since aluminium is a metal, therefore field inside this will be zero. Hence it would not affect the field in between the two plates, so capacity =Vq​=Edq​ remains unchanged.

Since aluminium is a metal, therefore field inside this will be zero. Hence it would not affect the field in between the two plates, so capacity $= \frac{q}{V} = \frac{q}{E d}$ remains unchanged.