Arrhenius equations for two chemical reactions are k1 = A1e- E1 /RT , k2 = A2e-E2/RT . If E1 E2 then at a given temperature T,

Question

Arrhenius equations for two chemical reactions are k1 = A1e- E1 /RT , k2 = A2e-E2/RT . If E1 > E2 then at a given temperature T, (A) (k1/k2) < (A1/A2) (B) . (k2/k1) < (A2/A1) (C) k1k2 > A 1A2 (D) k1 + k2 > A1 + A2

Tardigrade Admin · Accepted Answer

(k1/A1) = e-E1/RT (k2/k2) =e-E2/RT Dividing eqn. (ii) by eqn. (i), (k2/A2) × (A1/k1) = e (E1-E2)/RT (k2/k1) × (A1/A2) > 1 ⇒ (A1/A2) > (k1/k2)

Q. Arrhenius equations for two chemical reactions are $k_{1} = A_{1} e^{- E_{1} / RT}, k_{2} = A_{2} e^{- E_{2} / RT}$ . If $E_{1} > E_{2}$ then at a given temperature $T,$

$\frac{k _{1}}{k _{2}} < \frac{A _{1}}{A _{2}}$

$. \frac{k _{2}}{k _{1}} < \frac{A _{2}}{A _{1}}$

$k_{1} k_{2} > A_{1} A_{2}$

$k_{1} + k_{2} > A_{1} + A_{2}$

Q. Arrhenius equations for two chemical reactions are k1​=A1​e−E1​/RT,k2​=A2​e−E2​/RT . If E1​>E2​ then at a given temperature T,

k2​k1​​<A2​A1​​

.k1​k2​​<A1​A2​​

k1​k2​>A1​A2​

k1​+k2​>A1​+A2​

A1​k1​​=e−E1/RT k2​k2​​=e−E2​/RT Dividing eqn. (ii) by eqn. (i), A2​k2​​×k1​A1​​=e(E1​−E2​)/RT k1​k2​​×A2​A1​​>1⇒A2​A1​​>k2​k1​​

Q. Arrhenius equations for two chemical reactions are $k_{1} = A_{1} e^{- E_{1} / RT}, k_{2} = A_{2} e^{- E_{2} / RT}$ . If $E_{1} > E_{2}$ then at a given temperature $T,$

$\frac{k _{1}}{k _{2}} < \frac{A _{1}}{A _{2}}$

$. \frac{k _{2}}{k _{1}} < \frac{A _{2}}{A _{1}}$

$k_{1} k_{2} > A_{1} A_{2}$

$k_{1} + k_{2} > A_{1} + A_{2}$